0=x^2+16x-5

Solution for 0=x^2+16x-5 equation:

0=x^2+16x-5

We move all terms to the left:

0-(x^2+16x-5)=0

We add all the numbers together, and all the variables

-(x^2+16x-5)=0

We get rid of parentheses

-x^2-16x+5=0

We add all the numbers together, and all the variables

-1x^2-16x+5=0

a = -1; b = -16; c = +5;
Δ = b2-4ac
Δ = -162-4·(-1)·5
Δ = 276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{276}=\sqrt{4*69}=\sqrt{4}*\sqrt{69}=2\sqrt{69}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{69}}{2*-1}=\frac{16-2\sqrt{69}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{69}}{2*-1}=\frac{16+2\sqrt{69}}{-2}
$